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The integrating factor of the differential equation $x\large\frac{dy}{dx}$$-y=2x^2 $ is


1 Answer

  • If the equation is of the form $\large\frac{dy}{dx}$$ + py= Q$, then the integrating factor is $e^{\large\int pdx}$
The equation can be rewritten as $\large\frac{dy}{dx }-\frac{ y}{x} =$$ 2x^2$
Here $p = \large\frac{-1}{x}$ and $Q = 2x^2$
Hence the integral Factor is $e^{\int (\large\frac{-1}{x})}dx = e^{\large-\log x} = e^{\large \log(1/x)} = 1/x$
Hence C is the correct answer.
answered Jul 30, 2013 by sreemathi.v