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TN XII Math
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Differential Calculus Applications - II
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Find the differential of the functions.$y$=$4\sqrt{x}$
This question has multiple parts. Therefore each part has been answered as a separate question on Clay6.com
tnstate
class12
bookproblem
ch6
sec-1
exercise6-1
p74
q1
q1-2
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asked
Apr 24, 2013
by
poojasapani_1
edited
Aug 12, 2013
by
meena.p
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Toolbox:
Let $y=f(x)$ be a differentiable function then the quantities $dx$ and $dy$ are called differentials.The differential $dx$ is an independent variable.
The differential $dy$ is then defined by $dy=f'(x)dx(dx \approx \Delta x)$
Also $f(x+\Delta x)-f(x)=\Delta y =dy $ from which $f(x+\Delta x) $can be evaluated
Given $ y=4 \sqrt x$
$y=x^{\large\frac{1}{4}}$
$\therefore dy=x^{\Large\frac{-3}{4}}dx$
$\qquad= \large\frac{dx}{x^{\Large\frac{3}{4}}}$
answered
Aug 12, 2013
by
meena.p
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