logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

Find the differential of the functions. $y$=$\large\frac{x-2}{2x+3}$

This question has multiple parts. Therefore each part has been answered as a separate question on Clay6.com
Can you answer this question?
 
 

1 Answer

0 votes
Toolbox:
  • Let $y=f(x)$ be a differentiable function then the quantities $dx$ and $dy$ are called differentials.The differential $dx$ is an independent variable.
  • The differential $dy$ is then defined by $dy=f'(x)dx(dx \approx \Delta x)$
  • Also $f(x+\Delta x)-f(x)=\Delta y =dy $ from which $f(x+\Delta x) $can be evaluated
Given $y=\large\frac{x-2}{2x+3}$
$dy=\large\frac{(2x+3)(1)-(x-2)(2)}{(2x+3)^2}$$dx$
$\quad=\large\frac{7}{(2x+3)^2}$$dx$
answered Aug 12, 2013 by meena.p
 
Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...