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TN XII Math
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Differential Calculus Applications - II
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Find the differential of the functions.$y$=$x\tan$$x$
This question has multiple parts. Therefore each part has been answered as a separate question on Clay6.com
tnstate
class12
bookproblem
ch6
sec-1
exercise6-1
p73
q1
q1-6
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asked
Apr 24, 2013
by
poojasapani_1
edited
Aug 12, 2013
by
meena.p
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Toolbox:
Let $y=f(x)$ be a differentiable function then the quantities $dx$ and $dy$ are called differentials.The differential $dx$ is an independent variable.
The differential $dy$ is then defined by $dy=f'(x)dx(dx \approx \Delta x)$
Also $f(x+\Delta x)-f(x)=\Delta y =dy $ from which $f(x+\Delta x) $can be evaluated
Given $y=x \tan x $
$dy= (\tan x+x \sec^2 x) dx$
answered
Aug 12, 2013
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