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Verify $\large\frac{\partial ^{2} y}{\partial x\partial y}=\frac{\partial ^{2} y}{\partial y\partial x}$ for the following function;$\;u=x^{2}+3xy+y^{2}$

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Toolbox:
• If $u=f(x,y)$ is the function of two independent variables then
• $\large\frac{\partial u}{\partial y (x_0,y_0)}=\frac{d}{dy}$$f(x_0,y)\;and \;\large\frac{\partial u}{\partial x(x_0,y_0)}=\large\frac{d}{dy}$$ f(x,y_0)$ Provided they exist
• The Second order parral derivaties are $\large\frac{\partial}{\partial x} \frac{\partial u}{\partial y}=\frac{\partial ^2 u}{\partial x \partial y},\frac{\partial}{\partial y} \frac{\partial u}{\partial y}=\frac{\partial ^2 u}{\partial y^2},\frac{\partial}{\partial y} \frac{\partial u}{\partial x}=\frac{\partial ^2 u}{\partial y \partial x},$$\;and\;\large\frac{\partial}{\partial x} \frac{\partial u}{\partial x}=\frac{\partial ^2 u}{\partial x ^2} Partial derivatives of functions of more similarly defined Given u=x^2+3xy+y^2 Step 1: \large\frac{\partial u}{\partial y}$$=3x+2y$
$\large\frac{\partial^2 u}{\partial x \partial y}$$=3 Step 2: \large\frac{\partial u}{\partial x}$$=2x+3y$