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Evaluate: $\int\limits_{0}^{\large\frac{\pi}{2}}\cos^{9} x dx $

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  • $\int \limits_0^{\large\frac{\pi}{2}} \sin ^n x dx$$=\int \limits_0^{\large\frac{\pi}{2}} \cos ^n x dx= \left\{ \begin{array}{1 1} \large\frac{n-1}{n}.\frac{n-3}{n-2}.\frac{n-5}{n-4}...\frac{2}{3}\; \normalsize when\; n\; is\; odd \\ \large\frac{n-1}{n}.\frac{n-3}{n-2}.\frac{n-5}{n-4}...\frac{1}{2}\frac{\pi}{2} \normalsize \;when\; n\; is\; even\; \end{array} \right. $
$\int\limits_{0}^{\large\frac{\pi}{2}}\cos^{9} x dx $
$\qquad= \large\frac{8}{9}.\frac{6}{7}.\frac{4}{5}.\frac{2}{3}$
$\qquad=\large\frac{128}{315}$
answered Aug 14, 2013 by meena.p
 
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