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What is the domain of $f(x)=\large\frac{[x]+1}{[x]-1}$ where $[x]$ is greatest integer function

$\begin{array}{1 1} (1,20) \\ [1,2] \\ (-\infty,1)\cup [2,\infty) \\ (-\infty,1]\cup [2,\infty) \end{array}$

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1 Answer

For f(x) to be defined $[x]-1\neq0$
$\Rightarrow\:[x]\neq 1$
$\Rightarrow\:x$ is any Real number and $x\notin [1,2)$
$x\in (-\infty,1)\cup [2,\infty)$
answered May 2, 2013 by rvidyagovindarajan_1
 
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