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Which of the following function are increasing or decreasing on the interval given? $x^{2}-1 $on$[0 , 1]$

Note: This is part 1st of a 5 part question, split as 5 separate questions here.

1 Answer

  • (i) If $f'$ is positive on an open interval $I$. Then $f$ is strictly increasing on $I$
  • (ii) If $f'$ is negative on an open interval $I$, then $f$ is strictly decreasing on $I$
$f(x)=x^2-1$ and the interval is $[0,1]$
$f'(x)=2x \geq 0$ on $[0,1]$
$\therefore f(x)$ is increasing on $[0,1]$
answered Jul 29, 2013 by meena.p

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