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Find the critical numbers and stationary points of each of the following functions. $\;f(\theta)=\sin^{2} 2\theta \;$in$\;[0 , \pi ]$

Note: This is part 5 of a 6 part question, split as 6 separate questions here.

1 Answer

  • A ciritical number of a function f is a number c in the domain of f such that either $f'(c)=0$ or $f'(c)$ does not exist.
  • Stationary points correspond to critical numbers for which $f'(c)=0$
$f(0)=\sin ^2 2 \theta$ on $[0,2 \pi]$
Step 1:
$f'(\theta)=2 \sin 2 \theta \cos 2 \theta.2$
$\qquad= 4 \sin 2 \theta \cos 2 \theta$
$\qquad=2 \sin 4 \theta$
$f'(0)=0=>2 \sin 4 \theta=0$
$4 \theta=n \pi=>n =z$
$\theta= \large\frac{n \pi}{4} $$ n \in z$
Step 2:
The values of $\theta$ in $[0, \pi]$ are $0, \large\frac{\pi}{4},\frac{\pi}{2}, \frac{3 \pi}{4}$$,\pi$ (critical number)
The critical points are $(0,0), (\large\frac{\pi}{4}$$,1), (\large\frac{\pi}{2},$$0),(\large\frac{3 \pi}{4}$$,1),(\pi,0)$
answered Jul 31, 2013 by meena.p

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