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If the matrix $\begin{bmatrix} -1 & 3 & 2 \\1 & k & -3 \\1 & 4 & 5 \end{bmatrix}$ has an inverse than the value of $k$

\[\begin{array}{1 1} (1)k\; is\; any\; real \;number& (2)k=-4\\(3)k\neq -4&(4)k\neq 4\end{array}\]

Can you answer this question?
 
 

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$A=\begin{bmatrix} -1 & 3 & 2 \\1 & k & -3 \\1 & 4 & 5 \end{bmatrix}$
Given that $A^{-1}$ exists.
$|A| \neq 0$
$| A | =\begin{vmatrix} -1 & 3 & 2 \\1 & k & -3 \\1 & 4 & 5 \end{vmatrix}$
$ -1 (5 k +12)-3 -3(5+3)$
$ +2(4-k) \neq 0$
$-5k-12-15-9+8-2k \neq 0$
$-7 -28 \neq 0$
$7+28 \neq 0$
$7 (k+4) \neq 0$
$k+4 \neq 0$
$k \neq -4$
Hence 3 is the correct answer.
answered May 2, 2014 by meena.p
 

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