The general solution of the differential equation\(\frac{\large dy}{\large dx}=e^{x+y}\)is

Question

\[ \begin{array}{1 1}(A)\;e^x+e^{-y}=C\qquad(B)\;e^x+e^y=C\\(C)\;e^{-x}+e^y=C\qquad(D)\;e^{-x}+e^{-y}=C\end{array}\]