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If $\overrightarrow{a}$ and $\overrightarrow{b}$ are two unit vectors and $\theta $is the angle between them, then $(\overrightarrow{a}+\overrightarrow{b})$ is a unit vector if

\[\begin{array}{1 1}(1)\theta =\large\frac{\pi}{3}& (2)\theta =\large\frac{\pi}{4}\\ (3)\theta=\large\frac{\pi}{2}& (4)\theta=\large\frac{2\pi}{3}\end{array}\]

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Given $|\overrightarrow{a}|=1$ and $|\overrightarrow{b}| =1$
$\theta$ is the angle between $\overrightarrow{a}$ and $\overrightarrow{b}$
$\overrightarrow{a^2}+\overrightarrow{b^2}+2|\overrightarrow{a}||\overrightarrow{b}| \cos \theta=1$
$\overrightarrow{|a|^2}+\overrightarrow{|b|^2}+2|\overrightarrow{a}||\overrightarrow{b}| \cos \theta=1$
$1^2+1^2+2 \times 1\times 1 \cos \theta=1$
$\cos \theta = -\large\frac{1}{2}$
$\theta$ lies in the second quadrant
Hence 4 is the correct answer.
answered May 5, 2014 by meena.p

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