# Find the equation of a curve passing through the point (0,-2) given that at any point (x,y) on the curve,the product of the slope of its tangent and y coordinate of the point is equal to the x coordinate of the point.

Toolbox:
• $\int x = \large\frac{x^2}{2}$$+ C Step 1: According to the given information we get the equation as y\large\frac{dy}{dx}$$ = x$
$ydy = xdx$
Integrating on both sides we get,
$\large\frac{y^2}{2} =\frac{ x^2}{2}$$+ C y^2 - \large\frac{x^2}{2}$$ = C$
Step 2:
Since the curve passes through (0,-2), we substituting for $x$ and $y$ to find the value for C
$(-2)^2 - 0 = 2C$