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The equation of the line parallel to $\large\frac{x-3}{1}=\frac{y+3}{5}=\frac{2z-5}{3}$ and passing through the point $(1 , 2 ,5 ) $ in vector form is

(1)$\overrightarrow{r}=(\overrightarrow{i}+\overrightarrow{5j}+\overrightarrow{3k})+ t(\overrightarrow{i}+\overrightarrow{3j}+\overrightarrow{5k}) $\[\](2)$\overrightarrow{r}=(\overrightarrow{i}+\overrightarrow{3j}+\overrightarrow{5k})+ t(\overrightarrow{i}+\overrightarrow{5j}+\overrightarrow{3k})$ \[\](3)$\overrightarrow{r}=(\overrightarrow{i}+\overrightarrow{5j}+\frac{3}{2}\overrightarrow{k})+ t(\overrightarrow{i}+\overrightarrow{3j}+\overrightarrow{5k}) $\[\](4)$\overrightarrow{r}=(\overrightarrow{i}+\overrightarrow{3j}+\overrightarrow{5k})+ t(\overrightarrow{i}+\overrightarrow{5j}+\frac{3}{2}\overrightarrow{k})$

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