# If$[\overrightarrow{a}\times\overrightarrow{b},\overrightarrow{b}\times\overrightarrow{c},\overrightarrow{c}\times\overrightarrow{a}]=64$ then $[\overrightarrow{a},\overrightarrow{b},\overrightarrow{c}]$ is

$\begin{array}{1 1}(1)32&(2)8\\(3)128&(4)0\end{array}$