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If$[\overrightarrow{a}\times\overrightarrow{b},\overrightarrow{b}\times\overrightarrow{c},\overrightarrow{c}\times\overrightarrow{a}]=64$ then $[\overrightarrow{a},\overrightarrow{b},\overrightarrow{c}]$ is

\[\begin{array}{1 1}(1)32&(2)8\\(3)128&(4)0\end{array}\]

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$[\overrightarrow{a}\times\overrightarrow{b},\overrightarrow{b}\times\overrightarrow{c},\overrightarrow{c}\times\overrightarrow{a}]=$$[\overrightarrow{a},\overrightarrow{b},\overrightarrow{c}]^2$
$64=[\overrightarrow{a},\overrightarrow{b},\overrightarrow{c}]^2$
$[\overrightarrow{a},\overrightarrow{b},\overrightarrow{c}]=\sqrt {64}$
$\qquad\qquad=8$
Hence 2 is the correct answer.
answered May 12, 2014 by meena.p
 

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