# The value of $[\overrightarrow{i}+\overrightarrow{j},\overrightarrow{j}+\overrightarrow{k},\overrightarrow{k}+\overrightarrow{i}]$ is equal to

$\begin{array}{1 1}(1)0&(2)1\\(3)2&(4)4\end{array}$

$[\overrightarrow{i}+\overrightarrow{j},\overrightarrow{j}+\overrightarrow{k},\overrightarrow{k}+\overrightarrow{i}] =2[\overrightarrow{i},\overrightarrow{j},\overrightarrow{k}]$
$\qquad= 2 \times 1$
Since $[\overrightarrow{i}\;\overrightarrow{j},\overrightarrow{k}]=1$
Hence 3 is the correct answer.