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The value of $[\overrightarrow{i}+\overrightarrow{j},\overrightarrow{j}+\overrightarrow{k},\overrightarrow{k}+\overrightarrow{i}] $ is equal to

\[\begin{array}{1 1}(1)0&(2)1\\(3)2&(4)4\end{array}\]

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$[\overrightarrow{i}+\overrightarrow{j},\overrightarrow{j}+\overrightarrow{k},\overrightarrow{k}+\overrightarrow{i}] =2[\overrightarrow{i},\overrightarrow{j},\overrightarrow{k}]$
$\qquad= 2 \times 1$
Since $[\overrightarrow{i}\;\overrightarrow{j},\overrightarrow{k}]=1$
Hence 3 is the correct answer.
answered May 13, 2014 by meena.p
 

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