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Q)

The point of intersection of the lines $\large\frac{x-6}{-6}=\frac{y+4}{4}=\frac{z-4}{-8} $ and $\large\frac{x+1}{2}=\frac{y+2}{4}=\frac{z+3}{-2}$ is

\[\begin{array}{1 1}(1)(0 , 0 ,-4 )&(2)(1 , 0 , 0 )\\(3)(0 , 2 , 0 )&(4)(1 , 2 , 0 )\end{array}\]

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A)
The equation of the give lines are
$\large\frac{x-6}{-6}=\frac{y+4}{4}=\frac{z-4}{-8} $-----(1)
$\large\frac{x+1}{2}=\frac{y+2}{4}=\frac{z+3}{-2}$----(2)
(0,0.-4) is the only point common to (1) and (2)
Hence (1) is the correct answer
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