logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

The point of intersection of the lines $\large\frac{x-6}{-6}=\frac{y+4}{4}=\frac{z-4}{-8} $ and $\large\frac{x+1}{2}=\frac{y+2}{4}=\frac{z+3}{-2}$ is

\[\begin{array}{1 1}(1)(0 , 0 ,-4 )&(2)(1 , 0 , 0 )\\(3)(0 , 2 , 0 )&(4)(1 , 2 , 0 )\end{array}\]

Can you answer this question?
 
 

1 Answer

0 votes
The equation of the give lines are
$\large\frac{x-6}{-6}=\frac{y+4}{4}=\frac{z-4}{-8} $-----(1)
$\large\frac{x+1}{2}=\frac{y+2}{4}=\frac{z+3}{-2}$----(2)
(0,0.-4) is the only point common to (1) and (2)
Hence (1) is the correct answer
answered May 13, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...