The shortest distance between the parallel lines $ \large\frac{x-3}{4}=\frac{y-1}{2}=\frac{z-5}{-3} $ and $\large\frac{x-1}{4}=\frac{y-2}{2}=\frac{z-3}{3}$ is

Question

\[\begin{array}{1 1}(1)3&(2)2\\(3)1&(4)0\end{array}\]