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Home  >>  CBSE XII  >>  Math  >>  Differential Equations
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Find the general solution $x^5\large\frac{dy}{dx}$$=-y^5$

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  • $\int\large\frac{ 1}{x^5} =\frac{ x^{-4}}{-4}$
Step 1:
Given: $x^5\large\frac{dy}{dx} $$= -y^5$
Seperating the variables we get,
$\large\frac{dy}{y^5} = -\frac{ dx}{x^5}$
Step 2:
integrating on both sides we get,
$\int y^{-5} dy = \int x^{-5} dx$
$\large\frac{y^{-4}}{-4 }=-\frac{x^{-4}}{-4}$$ + C$
$x^{-4} + y^{-4} =$$ C$
answered Aug 15, 2013 by sreemathi.v
 
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