\[\begin{array}{1 1}(1)(-3 , 4 , -5 ),49 &(2)(-6 , 8 ,-10 ),1 \\(3)(3 , -4 , 5 ),7&(4)(6 , -8 , 10 ),7\end{array}\]

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

The equation of the sphere is

$x^2+y^2+z^2-6x+8y-10z+1=0$

Comparing with the equation

$x^2+y^2+z^2+2gx+2fy+2hz+c=0$

Center is $(-g,-f,-h)$

Radius $\sqrt {g^2+f^2+h^2-c}$

Comparing equations

$2g=-6, \; 2f=8\;, 2h=-10,\;c=1$

$g=-3,f=4,h=-5,c=1$

Centre $(3,-4,5)$

Radius $\sqrt {(-3)^2+4^2+(-5)^2-1}$

$\qquad= \sqrt {9+16+25-1}$

$\qquad= \sqrt {49}=7$

Hence 3 is the correct answer.

Ask Question

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...