\[\begin{array}{1 1}(1)z_{1}+z_{4}=z_{2}+z_{3}&(2)z_{1}+z_{3}=z_{2}+z_{4}\\(3)z_{1}+z_{2}=z_{3}+z_{4}&(4)z_{1}-z_{2}=z_{3}-z_{4}\end{array}\]

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

Let $z_1,z_2,z_3,z_4$ denotes the vertices of the parallelogram ABCD.

Mid point of $AC=\large\frac{z_1+z_2}{2}$

Mid point of $AC=\large\frac{z_2+z_4}{2}$

In a parallelogram diagonal intersect in the mid point

$\large\frac{z_1+z_3}{2} =\frac{z_2+z_4}{2}$

$z_1+z_3=z_2+z_4$

Hence 2 is the correct answer.

Ask Question

Take Test

x

JEE MAIN, CBSE, AIPMT Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...