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If $z$ represents a complex number then arg $(z)+arg(\overline{z})$ is

\[\begin{array}{1 1}(1)\pi/4&(2)\pi/2\\(3)0&(4)\pi/4\end{array}\]

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1 Answer

$arg (z) +arg( \bar z)=arg(z) -arg(z)$
$\qquad=0$
hence 3 is the correct answer.
answered May 14, 2014 by meena.p
 

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