# If $-\overline{z}$ lies in the third quadrant then $z$ lies in the

$\begin{array}{1 1}(1)first\; quadrant&(2)second\;quadrant\\(3)third\;quadrant&(4)fourth\;quadrant\end{array}$

Given $-\bar {z}$ lies i the third quadrant
$\therefore - \bar{z}=-x -iy$
$-\bar {z} =x+iy$
$\bar {\bar{z}}= \overline {x+iy}$
$z= x-iy$
z lies i the fourth quadrant
Hence 4 is the correct answer.