# The focus of the parabola $x^{2}=16y$ is

$\begin{array}{1 1}(1)(4 , 0)&(2)(0 , 4 )\\(3)(-4 , 0)&(4)(0 , -4 )\end {array}$

$x^2=16 \;y$
$x^2=4(4)y,a=4$
The focus is $(0,4)$
Hence 2 is the correct answer.