\[\begin{array}{1 1}(1)\frac{1}{3}&(2)\frac{2}{3}\\(3)\frac{4}{9}&(4)\frac{2}{\sqrt{5}}\end{array}\]

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$9x^2+5y^2-54x-40y+116=0$

$9x^2+54x+5y^2-40y+116=0$

$9[x^2-6x]+5[y^2-8y]+116=0$

$9[(x-3)^2-3^2]+5[(y-4)^2-4^2]+116=0$

$9(x-3)^2-81+5(y-4)^2-80+116=0$

$9(x-3)^2+5(y-4)^2-45=0$

$9(x-3)^2+5(y-4)^2=45$

$\large\frac{9(x-3)^2}{5} +\frac{5 (y-4)^2}{45}$$=1$

$\large\frac{(x-3)^2}{5} +\frac {(y-4)}{9}$$=1$

$a^2=9,b^2=5$

$e= \sqrt {1-\large\frac{b^2}{a^2}}$

$\qquad= \sqrt {1- \large\frac{5}{9}}$

$\qquad=\sqrt {\large\frac{4}{9}}$

$e= \large\frac{2}{3}$

Hence 2 is the correct answer.

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