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TN XII Math
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Objective type Questions and Answers
The length of the semi-major and the length of the semi-minor axis of the ellipse $\large\frac{x^{2}}{144}+\frac{y^{2}}{169}$=$1$ are
\[\begin{array}{1 1}(1)26 , 12 &(2)13 , 24 \\(3)12 , 26 &(4) 13 , 12 \end{array}\]
tnstate
class12
bookproblem
p274
objective
q97
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asked
May 13, 2013
by
poojasapani_1
edited
May 17, 2013
by
poojasapani_1
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1 Answer
$\large\frac{x^2}{144} +\frac{y^2}{169}$$=1$
$\large\frac{x^2}{12^2} +\frac{y^2}{13^2}$$=1$
$a^2= 13^2; ^2= 12^2$
length of semi major axis =13
length of semi mior axis =12
Hence 4 is the correct answer.
answered
May 16, 2014
by
meena.p
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