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The length of the semi-major and the length of the semi-minor axis of the ellipse $\large\frac{x^{2}}{144}+\frac{y^{2}}{169}$=$1$ are

\[\begin{array}{1 1}(1)26 , 12 &(2)13 , 24 \\(3)12 , 26 &(4) 13 , 12 \end{array}\]

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$\large\frac{x^2}{144} +\frac{y^2}{169}$$=1$
$\large\frac{x^2}{12^2} +\frac{y^2}{13^2}$$=1$
$a^2= 13^2; ^2= 12^2$
length of semi major axis =13
length of semi mior axis =12
Hence 4 is the correct answer.
answered May 16, 2014 by meena.p
 

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