\[\begin{array}{1 1}(1)4&(2)6\\(3)8&(4)2\end{array}\]

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$9x^2+5y^2=180$

$\large\frac{9x^2}{180} +\frac{5y^2}{180}$$=1$

$\large\frac{x^2}{20} +\frac{y^2}{36}$$=0$

$a^2=36$

$b^2=20$

$e= \sqrt {1- \large\frac{^2}{a^2}}$

$\quad= \sqrt { \large\frac{16}{36}}$

$\quad=\large\frac{4}{9}$

$e=\large\frac{2}{3}$

Distance between the foci $=2ae$

$\quad= 2 \times 6 \times \large\frac{2}{3}$$=8$

Hence 3 is the correct answer

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