Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

If the length of major and semi-minor axis of an ellipse are $8 , 2 $ and their corresponding equations are $y-6=0 $ and $x+4=0 $ then the equations of the ellipse is

\[\begin{array}{1 1}(1)\large\frac{(x+4)^{2}}{4}+\frac{(y-6)^{2}}{16}=1&(2)\frac{(x+4)^{2}}{16}+\frac{(y-6)^{2}}{4}=1\\(3)\frac{(x+4)^{2}}{16}-\frac{(y-6)^{2}}{4}=1&(4)\frac{(x+4)^{2}}{4}-\frac{(y-6)^{2}}{16}=1\end{array}\]

Can you answer this question?

1 Answer

0 votes
Length of major axis $2a=8 => a=4$
Length of semi minor axis $b=2$
Equation of major axis $y-6=0$
Equation of minor axis $x+4=0$
$\therefore $ The equation of the ellipse is
Hence 2 is the correct answer.
answered May 16, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App