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Q)

The locus of foot of perpendicular from the focus to a tangent of the curve $ 16x^{2}+25y^{2}=400$ is

\[\begin{array}{1 1}(1)x^{2}+y^{2}=4&(2)x^{2}+y^{2}=25\\(3)x^{2}+y^{2}=16&(4)x^{2}+y^{2}=9\end{array}\]

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