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Home  >>  CBSE XII  >>  Math  >>  Relations and Functions
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If $f:R\rightarrow R$ is defined $f(x)=x^2-3$ then $f^{-1}x$ = ?

$\begin{array}{1 1} \sqrt {x+3} \\ \sqrt {x} +3 \\ x+ \sqrt 3 \\ none\;of\;these \end{array}$

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1 Answer

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$y=f(x)=x^2-3$
$\Rightarrow x=\sqrt{y+3}=f^{-1}(y)$
$\Rightarrow f^{-1}(x)=\sqrt{x+3}$
answered May 13, 2013 by rvidyagovindarajan_1
 

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