\[\begin{array}{1 1}(1)\frac{4}{9}&(2)\frac{2}{3}\\(3)\frac{9}{4}&(4)\frac{81}{16}\end{array}\]

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

The equation of the hyperbola is

$4x^2-y^2=36$

$\large\frac{4x^2}{36} -\frac{y^2}{36}$$=1$

$\large\frac{4x^2}{9} -\frac{y^2}{36}$$=1$----(1)

$a^2=9;$

$b^2=36$

The equation of the line is

$5x-2y+4k=0$

$2y=5x+4k$

$y= \large\frac{5}{2}$$+2k$----(2)

From equation (2) $m= \large\frac{5}{2}$$c= 2k$

$c^2= a^2m^2-b^2$

$(2k)^2 = 9 \bigg( \large\frac{5}{2} \bigg) ^2$$ -36$

$4k^2 = 9 \times \large\frac{25}{4} $$-36$

$4k^2 = \large\frac{225 -144}{4}$

$k^2=\large\frac{81}{16} $$=> k= \large\frac{9}{4}$

Hence 3 is the correct answer.

Ask Question

Tag:MathPhyChemBioOther

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...