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The equation of the chord of contact of tangents from $(2 , 1 )$ to the hyperbola $\large\frac{x^{2}}{16}-\frac{y^{2}}{9}$$=1 $ is

\[\begin{array}{1 1}(1)9x-8y-72=0&(2)9x+8y+72=0\\(3)8x-9y-72=0&(4)8x+9y+72=0\end{array}\]

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The equation of the chord of contact of tangent from (2,1) to the hyperola $ \large\frac{x^2}{16}-\frac{y^2}{9} $$=1$ is
$\large\frac{x \times 2}{16} -\frac{y \times 1}{9} $$=1$
$\large\frac{x}{8} -\frac{y}{9}$$=1$
=>$9x-8y-72=0$
Hence 1 is the correct answer.
answered May 16, 2014 by meena.p
 

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