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The slope of the tangent to the curve $y=3x^{2}+3\sin x $ at $x=0 $ is

\[\begin{array}{1 1}(1)3&(2)2\\(3)1&(4)-1\end{array}\]

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$y=3x^2+3 \sin x$
$\large\frac{dy}{dx}=$$6x+ 3 \cos x$
$\large\frac{dy}{dx} $$= 0+ 3 \cos 0 =3$
Hence 1 is the correct answer.
answered May 19, 2014 by meena.p
 

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