# The slope of the tangent to the curve $y=3x^{2}+3\sin x$ at $x=0$ is

$\begin{array}{1 1}(1)3&(2)2\\(3)1&(4)-1\end{array}$

$y=3x^2+3 \sin x$
$\large\frac{dy}{dx}=$$6x+ 3 \cos x \large\frac{dy}{dx}$$= 0+ 3 \cos 0 =3$
Hence 1 is the correct answer.
answered May 19, 2014 by