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If the normal to the curve $x^{2/3}+y^{2/3}=a^{2/3}$ makes an angle $\theta$ with the $x$-axis then the slope of the normal is

\[\begin{array}{1 1}(1)-\cot\theta&(2)\tan\theta\\(3)-\tan\theta&(4)\cot\theta\end{array}\]

1 Answer

Given the normal to the curve makes an angle $\theta$ with the x-axis
$=> \tan \theta$
Hence 2 is the correct answer.
answered May 19, 2014 by meena.p
 

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