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# The radius of a cylinder is increasing at the rate of $2$ cm/sec and its altitude is decreasing at the rate of $3$cm/sec . The rate of change of volume when the radius is $3$cm and the altitude is $5$cm is

$\begin{array}{1 1}(1)23\pi&(2)33\pi\\(3)43\pi&(4)53\pi\end{array}$

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## 1 Answer

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Let V be the volume, r be the radius h be the height of the cylinder for the time 't'.
$V= \pi r^2 h$

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