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If $V=\{x:\:x+2=0\}$, $\:R=\{x:\:x^2+2x=0\}$ and $\:\:S=\{x:\:x^2+x-2=0\}$, then for what value of $x$, $V=R=S$ ?

(A) 0 (B) -1 (C) -2 (D) 1
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Only when $x=-2, \:x+2=0,\:x^2+2x=0\:and\:x^2+x-2=0$
$\therefore$ at $x=-2$ V=R=S
answered May 15, 2013 by rvidyagovindarajan_1
edited May 17, 2014 by rohanmaheshwari0831_1

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