$\begin{array}{1 1} (A)\;y'' = 0 \\(B)\;y' = 0 \\ (C)\;xy'' = 0 \\ (D)\;y''' = 0 \end{array} $

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- Differentiation of $\large\frac{x}{a}$ is $\large\frac{1}{a}$
- Differentiation of $\large\frac{y}{b}$ is $\large\frac{y'}{b}$

Step 1:

Given :$\large\frac{x}{a} +\frac{ y}{b}$$ = 1$

Differentiating on both sides we get,

$\large\frac{1}{a }+ \frac{y'}{b}$$ = 0$

Step 2:

Again differentiating we get

$0 + [\large\frac{1}{b}]$$y'' = 0$

$y'' = 0$

This is the required solution.

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