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If the volume of an expanding cube is increasing at the rate of $4cm^{3}/sec $ then the rate of change of surface area when the volume of the cube is $8$ cubic cm is

\[\begin{array}{1 1}(1)8cm^{2}/sec&(2)16cm^{2}/sec\\(3)2cm^{2}/sec&(4)4cm^{2}/sec\end{array}\]

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