Let $S$ be the distance of the particle from a fixed o the lie at time 't' af 'v' be its velocity the $\large\frac{ds}{dt}$

Given $ v \alpha s^2$

ie $v= ks^2$

$\large\frac{dv}{dt} =k.$$ 2s. \large\frac{ds}{dt}$

$\qquad= 2ks.V$

$\qquad= 2ks .Vs$

Acceleration $=2k^2s^3$

Hence 3 is the correct answer.