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Home  >>  CBSE XII  >>  Math  >>  Vector Algebra
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Compute the magnitude of the following vectors: $(ii)\; \overrightarrow b = 2\hat i - 7 \hat j - 3\hat k $

This question has multiple parts. Therefore each part has been answered as a separate question on Clay6.com

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Toolbox:
  • The distance between the initial point and the terminal point of a vector is the magnitude (or length) of the vector $\overrightarrow{AB}$.It is denoted by $\mid\overrightarrow{AB}\mid$ or simply $AB$.
  • $\mid\overrightarrow{AB}\mid=\sqrt{a_1^2+a_2^2+a_3^2}$
  • Where $\overrightarrow{AB}=a_1\hat i+a_2\hat j+a_3\hat k.$
Step 1:
$\overrightarrow{b}=2\hat{i}-7\hat{j}-3\hat{k}$
Here $a_1=2,a_2=-7$ and $a_3=-3$
$\mid \overrightarrow{b}\mid=\sqrt{a_1^2+a_2^2+a_3^2}$
Step 2:
Hence $\mid\overrightarrow{b}\mid=\sqrt{2^2+(-7)^2+(-3)^2}$
$\qquad\qquad\;=\sqrt{4+49+9}$
$\qquad\qquad\;=\sqrt{62}$
answered May 16, 2013 by sreemathi.v
edited May 16, 2013 by sreemathi.v
 

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