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Find the value of p for which the quadratic equation(p+1)x^2 - 6(p+1)x + 3(

Find the value of p for which the quadratic equation(p+1)x^2 - 6(p+1)x + 3(p+q)=0, p is not equal to -1 has equal roots . Hence find the roots of the equation &value of q also . Ans:x=3,3 ;p=3; q=9.

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