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The function $f(x)=x^{2}$ is decreasing in

\[\begin{array}{1 1}(1)(-\infty ,\infty)&(2)(-\infty ,0 )\\(3)(0 , \infty)&(4)(-2 ,\infty)\end{array}\]

1 Answer

$f(x)=x^2$
$f'(x)=2x$
$f'(x) < 0\;if\; x <0$
$\therefore$ f(x) is decreasing in $(\infty,0)$
Hence 2 is the correct answer.
answered May 20, 2014 by meena.p
 
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