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# Verify that the given function(explicit or implicit)is a solution of the corresponding differential equation $y=x^2+2x+C\qquad:\;y'-2x-2=0$

Toolbox:
• Differentiation of $x^2 =2x$ and $2x =2$
Step 1:
Given $y = x^2 + 2x + C$
Differentiating on both sides we get,
$y' = 2x + 2$
Step 2:
Bringing all the terms to the LHS
we get $y' - 2x - 2 = 0$
Hence the answer is a solution to the given function.