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If $u=y\sin x,$ then $\large\frac{\partial^{2} u}{\partial x\partial y}$ is equal to

\[\begin{array}{1 1}(1)\cos x&(2)\cos y\\(3)\sin x&(4)0\end{array}\]

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$u= y \sin x$
$\large\frac{\partial u}{\partial y}$$ =\sin x$
$\large\frac{\partial }{\partial x} \bigg( \large\frac{\partial u}{\partial y} \bigg) $$=\cos x$
$\large\frac{\partial ^2 u}{\partial x \partial y} $$=\cos x$
Hence 1 is the correct answer. .
answered May 20, 2014 by meena.p
 

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