Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The curve $ay^{2}=x^{2}(3a-x)$ cuts the $y$-axis at

\[\begin{array}{1 1}(1)x=-3a,x=0&(2)x=0,x=3a\\(3)x=0,x=a&(4)x=0\end{array}\]

Can you answer this question?

1 Answer

0 votes
$ay^2 =x^2 (3a-x)$
The point of intersection with y-axis is obtained by putting $x=0$ in the equation of the curve.
$ay^2 =0 (3a -0)$
$y^2 =0 => y=0$
The curve intersect the y-axis at the origin ie $x=0$
Hence 4 is the correct answer.
answered May 20, 2014 by meena.p
Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App