logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

The value of $\int\limits_{-\pi/2}^{\pi/2}\large\left(\frac{\sin x}{2+\cos x}\right)$$dx$ is

\[\begin{array}{1 1}(1)0&(2)2\\(3)\log 2&(4)\log 4\end{array}\]

Can you answer this question?
 
 

1 Answer

0 votes
Let $f(x)=\large\frac{\sin x}{2+ \cos x}$
$f(-x)= \large\frac{\sin (-x )}{2+ \cos (-x)}$
$\qquad= \large\frac{\sin x }{-2+\cos x}$
$\qquad=-f(x)$
It is a odd function.
$\int\limits_{-\pi/2}^{\pi/2}\large\left(\frac{\sin x}{2+\cos x}\right)$$dx=0$
Hence 1 is the correct answer.
answered May 21, 2014 by meena.p
 
Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...