Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The area between the ellipse $\large\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}$=$1$ and its auxillary circle is

\[\begin{array}{1 1}(1)\pi b(a-b)&(2)2\pi a(a-b)\\(3)\pi a(a-b)&(4)2\pi b(a-b)\end{array}\]

Can you answer this question?

1 Answer

0 votes
The area of the ellipse $ \large\frac{x^2}{a^2} +\frac{y^2}{b^2} $$=1$ is $\pi a b$
The equation of the auxiliary circle of the ellipse $ \large\frac{x^2}{a^2} +\frac{y^2}{b^2} $ is $x^2+y^2$
Area of the auxiliary circle is
$x^2 +y^2 =a^2 \pi a^2$
Area between the auxiliary circle ad the ellipse $ = \pi a^2 - \pi ab$
$\qquad= \pi a (a-b)$
Hence 3 is the correct answer.
answered May 21, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App