# The volume of the solid obtained by revolving $\large\frac{x^{2}}{9}+\frac{y^{2}}{16}$$=1 about the minor axis is $\begin{array}{1 1}(1)48\pi&(2)64\pi\\(3)32\pi&(4)128\pi\end{array}$ Can you answer this question? ## 1 Answer 0 votes The equation of the give ellipse is \large\frac{x^2}{9} +\frac{y^2}{16}$$=1$
$a=4,b=3$