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The volume of the solid obtained by revolving $\large\frac{x^{2}}{9}+\frac{y^{2}}{16}$$=1$ about the minor axis is

\[\begin{array}{1 1}(1)48\pi&(2)64\pi\\(3)32\pi&(4)128\pi\end{array}\]

1 Answer

The equation of the give ellipse is $\large\frac{x^2}{9} +\frac{y^2}{16}$$=1$
Required volume $= \large\frac{4 \pi}{3} $$ \times 16 \times 3$
$\qquad= 64 \pi cu. uits$
Hence 2 is the correct answer.
answered May 21, 2014 by meena.p

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