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The length of the are of the curve $x^{2/3}+y^{2/3}=4$ is

\[\begin{array}{1 1}(1)48&(2)24\\(3)12&(4)96\end{array}\]

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$x^{2/3} +y^{2/3}-(2^3)^{2/3}$
Here $a =2^3$
Required length $=6a = 6 \times 8 =48$
Hence 1 is the correct answer.
answered May 21, 2014 by meena.p
 

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