logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

The integrating factor of $\large\frac{dy}{dx}$$+2\large \frac{y}{x}$$=e^{4x}$ is

\[\begin{array}{1 1}(1)\log x&(2)x^{2}\\(3)e^{x}&(4)x\end{array}\]

Can you answer this question?
 
 

1 Answer

0 votes
The integrating factor of $\large\frac{dy}{dx}$$+Py=Q$ is $e^{\int pdx}$
The given differential equation is $\large\frac{dy}{dx}+\frac{2}{x}$$.y=e^{4x}$
Comparing $P= \large\frac{2}{x}$
$I.F=e^{\int Pdx } =e^{\int \large\frac{2}{x}} $$dx$
$\quad= e^{2 \log x} =e^{\log x^2}= x^2$
Hence 2 is the correct answer.
answered May 21, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...